Answer #27

The answer is (b): the smaller bulb will glow more brightly, as seen in the figure at the right below.

A small light bulb has more resistance than a large one, so that it will pass less current and consume less power:

P=VI=V**2/R.

However, when the two bulbs are connected in series, the larger resistance has the greater voltage drop across it, while the currents in the two bulbs are the same:

P=VI,

so the smaller bulb consumes more power and therefore glows more brightly.


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